Long story short: I need the ISO Week. We need to be able to make sure that when we’re reporting, we’re pulling data for the full week (which happens to coincide with ISO Week at my employer).
The problem with using an existing function is that the existing functions just return the week and not the full year + week combination. I used the function from the Less Than Dot wiki as a starting point and added my own code to create the full YYYYWW string to give me an ISO Week. This isn’t actually in the ISO standard format for reporting the ISO week, but I also don’t care so long as I can use the ISOWeek for effective querying.
Enjoy
ALTER FUNCTION ISOweek (@DATE DATETIME)
RETURNS VARCHAR(6)
AS
BEGIN
DECLARE @ISOweek INT,
@year INT,
@rVal VARCHAR(6) ;
SET @ISOweek = DATEPART(wk, @DATE) + 1 - DATEPART(wk, CAST(DATEPART(yyyy, @DATE) AS CHAR(4)) + '0104') ;
SET @year = DATEPART(yyyy, @DATE) ;
SET @rVal = CAST(@year AS VARCHAR(4)) + RIGHT('00' + CAST(@ISOWeek AS VARCHAR(2)), 2)
--Special cases: Jan 1-3 may belong to the previous year
IF (@ISOweek = 0)
BEGIN
SET @rVal = dbo.ISOweek(CAST(DATEPART(yyyy, @DATE) - 1 AS CHAR(4))
+ '12'
+ CAST(24 + DATEPART(DAY, @DATE) AS CHAR(2)))
+ 1 ;
END
--Special case: Dec 29-31 may belong to the next year
IF (
(DATEPART(mm, @DATE) = 12)
AND ((DATEPART(dd, @DATE) - DATEPART(dw, @DATE)) >= 28)
)
BEGIN
SET @ISOweek = 1 ;
SET @year = DATEPART(yyyy, @DATE) + 1 ;
SET @rVal = CAST(DATEPART(yyyy, @DATE) + 1 AS VARCHAR(4)) + '01'
END
RETURN @rVal ;
END
GO
This lets me do some snazzy reporting hackery like this:
SELECT MIN(c2.[Date]) AS StartDate,
MAX(c2.[Date]) AS EndDate
FROM dbo.Calendar AS c
INNER JOIN dbo.Calendar AS c2 ON c.ISOWeek = c2.ISOWeek
WHERE c.[Date] = '20091229' ;
/*
StartDate EndDate
----------------------- -----------------------
2009-12-27 00:00:00.000 2010-01-02 00:00:00.000
*/
Which is then used to feed report parameters.
Comments
there is a problem with this, when @ISOWeek = 0 then @rVal value only bring back week number not year+week number.
Do you have a specific date that this fails for? Knowing where it fails makes it easier to fix.
Actually I think this is my error,
I had a ISOWeek function already so changed the name of this function but didnt change the call in the script! So it was using the old function! Sorry
But this script has helped me out no end, I have been fighting with ISOWeek and changing back to a date for graphing purposes! This helped no end!
Ouch! I’ve done that a lot myself, so no worries.
I’m glad to hear that it’s working well and saving you some pain. I had a lot of issues with ISO weeks myself. If you do run into a problem with the function let me know and I’ll take a look at it.